The capacities of the three capacitors are in ratio 1 - 2 - 3- Their equivalent capacity when connected in parallel is 60-11- F more than when they are connected in series- The individual capacities of capacitors in - F are-

C_p=x+2x+3x=6x (1) 1/C_s=1/x+1/2x+1/3x=11/6x C_s=6x/11 (2) C_p=60/11+Cs 6x=60/11+6x/11 66x 6x=60 60x=60 x=1 μ F C_1=1 μ F; C_2=2 μ F; ...

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Standard XII

Physics

New Capacitance in Dielectric

The capacitie...

Question

The capacities of the three capacitors are in ratio 1 : 2 : 3. Their equivalent capacity when connected in parallel is $\frac{60}{11} μ F$ more than when they are connected in series. The individual capacities of capacitors in $μ F$ are?

4, 6, 7

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1, 2, 3

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2, 3, 4

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1, 3, 6

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Solution

The correct option is B 1, 2, 3
$C_{p} = x + 2 x + 3 x = 6 x - - - - - (1)$
$\frac{1}{C_{s}} = \frac{1}{x} + \frac{1}{2 x} + \frac{1}{3 x} = \frac{11}{6 x}$
$C_{s} = \frac{6 x}{11} - - - - - - - - (2)$
$C_{p} = \frac{60}{11} + C s$
$6 x = \frac{60}{11} + \frac{6 x}{11}$
$66 x - 6 x = 60$
$60 x = 60 x = 1 μ F$
$C_{1} = 1 μ F; C_{2} = 2 μ F; C_{3} = 3 μ F$

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