The capacity between the adjacent plates of a parallel plate capacitor is10μF. If we want a capacity of 50μF, the number of plates to be used is
A
5
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B
50
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C
6
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D
4
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Solution
The correct option is C 6 Connecting n plates alternatively creates a total capacitance of (n−1)Aϵ0/d Therefore 6 plates of the mentioned capacitor can be used to get the required capacitance.