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Question

The capacity of a binary symmetric channel with a crossover probability of 0.25 will be

A
0.756 bits/symbol
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B
0.1887 bits/symbol
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C
0.094 bits/symbol
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D
1 bits/symbol
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Solution

The correct option is B 0.1887 bits/symbol
The capacity of BSC with p = 0.25 will be
C=1+plog2p+(1p)log2(p1) bits/symbol
= 0.1887 bits/symbol

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