Let the radius of the circular end be r.
Height (h) of the cylindrical vessel = 1 m
Volume of cylindrical vessel =15.4 litres=0.0154 m3
[Assume π=227]
πr2h=0.0514 m3
(227×r2×1)m=0.0154 m3
⇒r=0.07 m
Total surface area of the vessel =2πr(r+h)
[2×227×0.07(0.07+1)]m2
=0.44×1.07 m2
=0.4708 m2
Therefore, 0.4708 m2 of the metal sheet would be required to make the cylindrical vessel.