The capacity of a cylindrical tank is $6160$ m $^{3}$ . If the radius of its base is $14$ m, find the depth of the tank.

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Solution

Vol.of tank $= π r^{2} h = 6160 m^{3}$
As $r = 14 m \Rightarrow h = \frac{6160}{π (14)^{2}} = 10$

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The capacity of a cylindrical tank is 6160 m3. If the radius of its base is 14 m, find the depth of the tank.

Vol.of tank =πr2h=6160m3As r=14m⇒h=6160π(14)2=10

The capacity of a cylindrical tank is $6160$ m $^{3}$ . If the radius of its base is $14$ m, find the depth of the tank.

Vol.of tank $= π r^{2} h = 6160 m^{3}$
As $r = 14 m \Rightarrow h = \frac{6160}{π (14)^{2}} = 10$