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Question

The capacity of a parallel plate air capacitor is 2μF and voltage between the plates is changing at the rate of 3 V/s. The displacement current in the capacitor is :

A
2μA
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B
3μA
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C
5μA
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D
6μA
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Solution

The correct option is D 6μA
Charge across the plate of capacitor, q=CV
Differentiating w.r.t time, we get dqdt=CdVdt
Displacement current, i=CdVdt
Given : C=2μF
dVdt=3 V/s
Displacement current , i=2μF×3V/s=6μA

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