The capacity of a parallel plate capacitor is 10μF. This capacitor is divided into two equal parts and these parts are filled by media of dielectric constant 2 and 4. The new capacitance will be
A
20μF
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B
30μF
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C
10μF
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D
40μF
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Solution
The correct option is B30μF Given: k1=2;k2=4;C=10μF
As we know that capacitance of parallel plate capacitor is
C=ϵ0Ad=10μF.....(1)
From given diagram, we can say that the two parts can be treated as two capacitors in parallel, with separation d and plate area A2.