The capacity of a parallel plate condenser is $C$ .Its capacity when the separation between the plate in halved will be:

4 C

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2 C

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\frac{C}{2}

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\frac{C}{4}

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Solution

The correct option is A $4 C$
Given, $C a p a c i t y = c, d = \frac{d}{2}$

So, if the separation between the plate is decreased then the capacity will increase by $4$ times then the original.

Thus the capacitance is $4 C$

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The capacity of a parallel plate condenser is C.Its capacity when the separation between the plate in halved will be:

The correct option is A 4CGiven, Capacity=c,d=d2So, if the separation between the plate is decreased then the capacity will increase by4 times then the original.Thus the capacitance is 4C

The capacity of a parallel plate condenser is $C$ .Its capacity when the separation between the plate in halved will be:

The correct option is A $4 C$
Given, $C a p a c i t y = c, d = \frac{d}{2}$

So, if the separation between the plate is decreased then the capacity will increase by $4$ times then the original.

Thus the capacitance is $4 C$