The capacity of a parallel plate condenser with air medium is 60μF having distance of separation d . If the space between the plates is filled with two slabs each of thickness d/2 and dielectric constants 4 and 8, the effective capacity becomes :
A
160μ F
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B
320μ F
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C
640μ F
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D
360μ F
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Solution
The correct option is B 320μ F Given initial capacitance C=60μF ⇒60μF=ε0Ad When the distance is filled with materials with different dielectric medium we have two capacitance C1=k1ε0A(d2) and C2=k2ε0A(d2) in series. C1=4×60×2μFC2=8×60×2μF C1=480μF and C2=960μF We know, when capacitors are in series: 1ceff=1c1+1c2 ∴1ceff=1480+1960⇒Ceff=320μF.