The capacity of parallel plate air capacitor is 1μF and voltage between the plates is changing at the rate of 3 V/s the current in the capacitor is :
Given that,
Capacitor C=1μF
Changing at the rate =3v/s
We know that,
Q=CV...(I)
Q=It....(I)
Equating both equations
It=CV
I=CVt
I=1×10−6×3
I=3×10−6A
I=3μA
Hence, this is the required solution