The carbide which gives propyne on hydrolysis is :

Al4C3

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CaC2

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Fe3C

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Mg2C3

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Solution

The correct option is D
Mg2C3

$M g_{2} C_{3} + 2 H_{2} O \to 2 M g O + C_{3} H_{4}$

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Similar questions

C a C_{2}, A l_{4} C_{3} a n d M g_{2} C_{3}

H_{2} O

25^{o} C .

C a C_{2} (s) + 2 H_{2} O (l) \to C a (O H)_{2} (s) + C_{2} H_{2} (g)

A l_{4} C_{3} (s) + 12 H_{2} O (l) \to 4 A l (O H)_{3} (s) + 3 C H_{4} (g)

M g_{2} C_{3} (s) + 4 H_{2} O (l) \to 2 M g (O H)_{2} (s) + C H_{3} - C \equiv C H (g)

B e_{2} C, C a C_{2}, M g_{2} C_{3}, A l_{4} C_{3}, C H_{4},

Which is not obtained when metal carbides react with H₂O?

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