The cardinality of set $A = {(a, b) : a b = 36 where a and b are coprime to each other}$ is

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Solution

Factors of $36$ are ${1, 2, 3, 4, 6, 9, 12, 18, 36}$
$a, b$ are coprime
So, possible pairs are
$(1, 36), (4, 9), (9, 4), (36, 1)$
$A = {(1, 36), (4, 9), (9, 4), (36, 1)}$
Cardinality of $A$ is $4$

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Cardinality of Sets

Standard XII Mathematics

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The cardinality of set A={(a,b):ab=36 where a and b are coprime to each other} is

Factors of 36 are {1,2,3,4,6,9,12,18,36} a,b are coprime So, possible pairs are (1,36),(4,9),(9,4),(36,1) A={(1,36),(4,9),(9,4),(36,1)} Cardinality of A is 4

The cardinality of set $A = {(a, b) : a b = 36 where a and b are coprime to each other}$ is

Factors of $36$ are ${1, 2, 3, 4, 6, 9, 12, 18, 36}$
$a, b$ are coprime
So, possible pairs are
$(1, 36), (4, 9), (9, 4), (36, 1)$
$A = {(1, 36), (4, 9), (9, 4), (36, 1)}$
Cardinality of $A$ is $4$