The cardinality of set P is 3. What is the number of elements in the power set of set P ?
8

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Solution

The correct option is A 8
The cardinality of set P is 3
$\Rightarrow$ Number of elements in set P = 3
Number of elements in a power set = number of given subsets of a set = $2^{n}$
where n is the cardinality of the set
Hence, the number of elements in power set of p = $2^{3}$ = 8

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Similar questions

Find the cardinal number of the following sets :

(i) $A_{1} = {- 2, - 1, 1, 3, 5}$

(ii) $A_{2} = {x : x \in N a n d 3 \leq x < 7}$

(iii) $A_{3} = {p : p \in W a n d 2 p - 3 < 8}$

(iv) $A_{4} = {b : b \in Z a n d - 7 < 3 b - 1 \leq 2}$ $Cardinal~Number~of~set~:The number of elements in a set is called its Cardinal Number.$

A

1

P (A)

5

P

(A)

P (S)

S = {(ϕ), 1, (2, 3)}

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