The carpenter made a flat drawer which is rectangular, along with the shelf and told that the area of the drawer is equal to the area of the shelf. The height of the triangle with respect to hypotenuse as the base (B) is H and the length of the drawer is along the hypotenuse of the triangle. Find the breadth of the drawer.

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H/2

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H/3

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Solution

The correct option is C
H/2

$Area of triangular shelf = Area of rectangular drawer (\frac{1}{2}) \times B \times H = B \times b r e a d t h B r e a d t h = \frac{H}{2}$

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The correct option is C H/2 Area of triangular shelf= Area of rectangular drawer(12)×B×H=B×breadthBreadth=H2

The correct option is C
H/2

$Area of triangular shelf = Area of rectangular drawer (\frac{1}{2}) \times B \times H = B \times b r e a d t h B r e a d t h = \frac{H}{2}$