The cartesian co-ordinates of the point whose polar co-ordinates are as (5,π−tan−1(43)), are
A
(−3,−4)
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B
(−3,4)
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C
(3,−4)
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D
(3,4)
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Solution
The correct option is B(−3,4) (5,π−tan−1(43)) r=5,θ=π−tan−1(43) Since, θ=π−tan−1(43), and since the point lies in second quadrant, So, cosθ=−35,sinθ=45 We have x=rcosθ,y=rsinθ x=−3,y=4 So, the point is (−3,4).