The given equation of the line in Cartesian form is,
x−5 3 = y+4 7 = z−6 2 x−5 3 = y−( −4 ) 7 = z−6 2 (1)
The equation of the line in Cartesian form is represented as,
x− x ′ a = y− y ′ b = z− z ′ c (2)
Compare both the equations (1) and (2).
x ′ =5, y ′ =−4, z ′ =6 a=3,b=7,c=2
The vector form of the line equation is,
r → = a → +λ b → (3)
Where,
a → = x ′ i ^ + y ′ j ^ + z ′ k ^ , b → =a i ^ +b j ^ +c k ^ .
Substitute the values in a → , b → .
a → =5 i ^ −4 j ^ +6 k ^ , b → =3 i ^ +7 j ^ +2 k ^
Substitute the value of a → and b → in equation (3).
r → =( 5 i ^ −4 j ^ +6 k ^ )+λ( 3 i ^ +7 j ^ +2 k ^ )
Thus, the equation of the line in vector form is r → =( 5 i ^ −4 j ^ +6 k ^ )+λ( 3 i ^ +7 j ^ +2 k ^ ).