Question

The catalyst provides a new pathway involving lower amount of activation energy, to make the reaction fast. Which of the following is/are the result of catalytic action?

• A. Catalyst decreases $E_a/RT$ value.
• B. Catalyst increases $-E_a/RT$ value.
• C. Catalyst increases $e^{E_a/RT}$ value.
• D. Catalyst increases k of reaction.

Answer 1

Answer: (A), (B), (D)

The correct options are
A Catalyst decreases $E_a/RT$ value.
B Catalyst increases $-E_a/RT$ value.
D Catalyst increases k of reaction.

To increase the rate of reaction catalyst does
(i) Decrease $E_a$
(ii) Decrease $E_a/RT$
(iii) Increases $-E_a/RT$
(iv) Increase $e^{-E_a/RT}$
(v) Increase k.