The cathode of a photo electric cell is changed such that the work function changes from $W_{1} t o W_{2} (W_{1} > W_{2})$ . If the currents before and after change are $I_{1}$ and $I_{2}$ , all other conditions unchanged, then :
(assuming $h_{v} > W_{2})$

I_{1} = I_{2}

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I_{1} < I_{2}

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I_{1} > I_{2}

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I_{1} \leq I_{2}

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Solution

The correct option is A $I_{1} = I_{2}$
By changing work function, energy available for kinetic energy of electrons changes, there is no change in the intensity of the source light. So current will not change as current is dependent on the intensity of light.

So, $I_{1} = I_{2}$

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The cathode of a photoelectric cell is changed such that the work function changes from $W_{1} t o W_{2} (W_{2} > W_{1})$ . If the current before and after change are $l_{1} a n d l_{2}$ all other conditions remaining unchanged, then (assuming hn > $W_{2}$ )