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Thomson's Discovery of Electrons

The cathode r...

Question

The cathode ray experiment is conducted in a discharge tube containing four different gases A, B, C and D, the molecular weight of A = B > D > C, then e/m as observed will be:

A

A > B > D > C

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B

A < D < B < C

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C

A = B > D > C

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D

A = B = C = D

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Solution

The correct option is C A = B = C = D
Cathode rays in the discharge tube are electrons produced due to ionization of gas. Hence, they are independent of the nature of the gas.
Due to this, the $e / m$ ratio is same for all gases.

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