The cation that will not be precipitated by $H$ _2S $i n t h e p r e s e n c e o f d i l$ HCl$ is:

A s^{3 +}

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P b^{2 +}

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C u^{2 +}

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C o^{2 +}

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Solution

The correct option is D $C o^{2 +}$
$C o^{2 +}$ will not be precipitated by $H_{2} S$ in the presence of dil $H C l$ as dil $H C l$ will suppress the ionization of $H_{2} S$ .
To affect the precipitation, $H_{2} S$ should be used in the ammoniacal solution.

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