The ceiling of a hall is 40m high. For maximum horizontal distance, the angle at which the ball may be thrown with a speed of 56ms−1 without hitting the ceiling of the hall is
A
25∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
30∘
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
45∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
60∘
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B30∘ For the range to be maximum, H≤40m Since maximum height of a projectile, H=u2sin2θ2g ⇒40=u2sin2θ2×9.8 sin2θ=78456×56 ⇒sin2θ=14 ⇒sinθ=0.5 ⇒θ=30∘