Question

The cell constant of a given cell is $0.25c{m}^{-1}$. The resistance of a solution placed in this cell is measured to be $100ohm$. The conductivity of the solution in $Sc{m}^{-1}$ is:

• A. $0.25Sc{m}^{-1}$
• B. $0.025Sc{m}^{-1}$
• C. $0.0025Sc{m}^{-1}$
• D. None of the above

Answer 1

The correct option is C $0.0025Sc{m}^{-1}$

The conductivity $\left(\kappa \right)$ is the product of reciprocal of resistance $\left(\frac{1}{R}\right)$ and cell constant $\left(\frac{l}{a}\right)$.
Hence,
$\kappa =\frac{1}{R}\times \frac{l}{a}\kappa =\frac{1}{100ohm}\times 0.25c{m}^{-1}=0.0025Sc{m}^{-1}$.