Question

The cell constant of a given cell is $0.47$$c{m}^{-1}$. The resistance of a solution placed in this cell is measured to be $31.6$ ohm. The conductivity of the solution (in $S$ $c{m}^{-1}$ where $S$ has usual meaning) is:

• A. $0.15$
• B. $1.5$
• C. $0.015$
• D. $150$

Answer 1

The correct option is C $0.015$

The conductivity $\left(\kappa \right)$ is the product of reciprocal of resistance $\left(\frac{1}{R}\right)$ and cell constant $\left(\frac{l}{a}\right)$.

Hence, $\kappa =\frac{1}{R}\times \frac{l}{a}=\frac{1}{31.6ohm}\times 0.47{cm}^{-1}=0.015S{cm}^{-1}$.

Option C is correct.