Question

The cell constant of a given cell is $0.47c{m}^{-1}$. The resistance of a solution placed in this cell is measured to be $31.6ohm$. The conductivity of the solution in $Sc{m}^{-1}$ is:

• A. 0.15
• B. 1.5
• C. 0.015
• D. 150

Answer 1

The correct option is C 0.015

The conductivity $\left(\kappa \right)$ is the product of reciprocal of resistance $\left(\frac{1}{R}\right)$ and cell constant $\left(\frac{l}{a}\right)$.
Hence,
$\kappa =\frac{1}{R}\times \frac{l}{a}\kappa =\frac{1}{31.6ohm}\times 0.47c{m}^{-1}=0.015Sc{m}^{-1}$.
Option C is correct.