The cell reaction for the given cell is spontaneous if $P t, C l_{2_{(P_{1})}} (g) | C l^{-} (1.0 M) | | C l^{-} (2 M) | C l_{2_{(P_{2})}} (g), P t$

P_{1} > P_{2}

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2 P_{1} < P_{2}

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P_{1} = P_{2}

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2 P_{2} > P_{1}

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Solution

The correct option is B $2 P_{1} < P_{2}$
Cell reaction is
$C l_{2} (g) + 2 C l^{-} (a q) \to 2 C l^{-} (a q) + C l_{2} (g)$
$P_{2} 1 M 2 M P_{1}$

Since it is a concentration cell, $E_{c e l l}^{0} = 0$

$E_{c e l l} = 0 - \frac{0.0591}{2} l n \frac{2 P_{1}}{P_{2}} = \frac{0.0591}{2} l n \frac{P_{2}}{2 P_{1}}$

For spontaneous cell reaction $E_{c e l l} = + v e$ ie. $P_{2} > 2 P_{1}$

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