The cell reaction for the given cell is spontaneous if $P t, C l_{2_{(P_{1})}} (g) | C l^{-} (1.0 M) | | C l^{-} (2 M) | C l_{2_{(P_{2})}} (g), P t$

P_{1} > P_{2}

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2 P_{1} < P_{2}

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P_{1} = P_{2}

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2 P_{2} > P_{1}

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Solution

The correct option is B $2 P_{1} < P_{2}$
Cell reaction is
$C l_{2} (g) + 2 C l^{-} (a q) \to 2 C l^{-} (a q) + C l_{2} (g)$
$P_{2} 1 M 2 M P_{1}$

Since it is a concentration cell, $E_{c e l l}^{0} = 0$

$E_{c e l l} = 0 - \frac{0.0591}{2} l n \frac{2 P_{1}}{P_{2}} = \frac{0.0591}{2} l n \frac{P_{2}}{2 P_{1}}$

For spontaneous cell reaction $E_{c e l l} = + v e$ ie. $P_{2} > 2 P_{1}$

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Similar questions

P t, C l_{2_{(P_{1})}} (g) | C l^{-} (1.0 M) | | C l^{-} (2 M) | C l_{2_{(P_{2})}} (g), P t

P t | C l_{2} | P_{1} | C l^{-} (1 M) | | C l^{-} (1 M) | P t | C l_{2} P_{2}

P t | C l_{2} (P_{1} a t m) | C l^{-} (1 M) | C l_{2} (P_{2} a t m) | P t

P t | O_{2} (g, 1 a t m) | O H^{-} (1 M) | | C l^{-} (1 M) | C l_{2} (g, 1 a t m) | P t

{C l}_{2} + {2 e}^{-} \to {2 C l}^{-}

{P t}^{2 +} + {2 C l}^{-} \to P t + {C l}_{2}, E_{c e l l} = - 0.15 V

{P t}^{2 +} + {2 e}^{-} \to P t, E = 1.20 V

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