The cell reaction in a galvanic cell is
Cu(s)+2Ag+(aq)→Cu+2(aq)+2Ag(s)
Then the incorrect statement is
Its cell notation is Cu |Cu+2(aq) || Ag+(aq)| Ag
Ag electrode acts as the cathode and Cu electrode acts as the anode
electrons flow from copper rod to silver rod through the external circuit
Cu electrode is marked positive and Ag electrode is marked negative
Oxidation takes place at anode & reduction takes place at cathode.