Question

The cell representation of electrochemical cell using the cell reaction:
$Ni\left(s\right)+2F{e}^{3+}\to N{i}^{2+}+2F{e}^{2+}isNi\left(s\right)|N{i}^{2+}\left(aq\right)||F{e}^{3+}\left(aq\right),F{e}^{2+}\left(aq\right)$

• A. True
• B. False

Answer 1

The correct option is A True

Oxidation takes place at the anode, and the electrode must be $Ni|N{i}^{2+}$,
$Ni\left(s\right)\to N{i}^{2+}\left(aq\right)+2e$
and the reduction occurs at the cathode: $F{e}^{3+},F{e}^{2+}:$
$2F{e}^{3+}+2e^{-}\to 2F{e}^{2+}$
For every Ni atom oxidized, two $F{e}^{3+}$ ions are reduced. The electrons from the Ni metal will flow from the anode, pass the load, and then carry out the reduction at the surface of the cathode to reduce the ferric $\left(F{e}^{3+}\right)$ ions to ferrous ions.
The galvanic cell is:
$Ni\left(s\right)|N{i}^{2+}\left(aq\right)||F{e}^{3+}\left(aq\right),F{e}^{2+}\left(aq\right)$