The cell representation of the given reaction is-Zn s - Cu 2- Zn 2- Cu s A- Zn 2- Zn Cu - Cu 2-B- Zn - Zn 2- Cu 2- ICuC- Cu 2- Cu Zn - Zn 2-D- Cu - Cu 2- Zn 2- Zn

The correct option is B Zn|Zn2+||Cu2+ICu Zinc is oxidizing to Zn2+ and Cu2+ is reducing to Cu. Oxidation half reaction is written first in the cell repre ...

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Standard XII

Chemistry

Representation of Cell

The cell repr...

Question

The cell representation of the given reaction is:
Zn(s) + Cu²⁺ → Zn²⁺ + Cu(s)

Zn²⁺|Zn||Cu|Cu²⁺

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Zn|Zn²⁺||Cu²⁺ICu

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Cu|Cu²⁺||Zn²⁺|Zn

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Cu²⁺|Cu||Zn|Zn²⁺

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Solution

The correct option is B
Zn|Zn²⁺||Cu²⁺ICu

Zinc is oxidizing to Zn²⁺ and Cu²⁺ is reducing to Cu. Oxidation half reaction is written first in the cell representation and reduction half reaction is written afterwards

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The cell representation of the given reaction is: Zn(s) + Cu2+ → Zn2+ + Cu(s)

The correct option is B Zn|Zn2+||Cu2+ICu Zinc is oxidizing to Zn2+ and Cu2+ is reducing to Cu. Oxidation half reaction is written first in the cell representation and reduction half reaction is written afterwards

The cell representation of the given reaction is:
Zn(s) + Cu²⁺ → Zn²⁺ + Cu(s)

The correct option is B
Zn|Zn²⁺||Cu²⁺ICu

Zinc is oxidizing to Zn²⁺ and Cu²⁺ is reducing to Cu. Oxidation half reaction is written first in the cell representation and reduction half reaction is written afterwards