The cell, $Z n / {Z n}^{2} (1 M) / / {C u}^{2 +} (1 M) / C u$ ( $E_{c e l l}^{o} = 1.10 V$ ) was allowed to be completely discharged at $298 K$ The relative concentration of ${Z n}^{2 +}$ to ${C u}^{2 +}$ is:

37.3

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10^{37.3}

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9.65 \times 10^{4}

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antilog

(24.04)

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Solution

The correct option is C $10^{37.3}$
$E_{c e l l} = E^{o}_{c e l l} - \frac{0.0591}{n} 1 o g Q$

where Q= $\frac{[Z n^{2 +}]}{[C u^{2 +}]}$

$\frac{[Z n^{2 +}]}{[C u^{2 +}]}$ = $1 0^{37.3}$

$E_{c e l l} = E^{o}_{c e l l}$ - $\frac{0.0591}{n} 1 o g Q$

where Q = $\frac{[Z n^{2 +}]}{[C u^{2 +}]}$

$\frac{[Z n^{2 +}]}{[C u^{2 +}]}$ = $1 0^{37.3}$

Hence $1 0^{37.3}$ is the answer.

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The cell, Zn/Zn2(1M)//Cu2+(1M)/Cu (Eocell=1.10V) was allowed to be completely discharged at 298K The relative concentration of Zn2+ to Cu2+ is:

The correct option is C 1037.3Ecell=Eocell−0.0591n1ogQwhere Q=[Zn2+][Cu2+] [Zn2+][Cu2+] =1037.3 Ecell = Eocell -0.0591n1ogQ where Q =[Zn2+][Cu2+] [Zn2+][Cu2+] = 1037.3Hence 1037.3 is the answer.

The cell, $Z n / {Z n}^{2} (1 M) / / {C u}^{2 +} (1 M) / C u$ ( $E_{c e l l}^{o} = 1.10 V$ ) was allowed to be completely discharged at $298 K$ The relative concentration of ${Z n}^{2 +}$ to ${C u}^{2 +}$ is: