wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The center of the circle given by the equation x2+y24x+6y51=0 is .

A
(2,-3)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(-2,3)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(3,-2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(-3,2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (2,-3)
On comparing the given equation with the standard equation of circle i.e. x2+y2+2gx+2fy+c=0, We get:
2g=-4 and 2f=6
g=-2 and f=3
Also the center of the circle is (-g,-f)
the center of the given circle will be (2,-3)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon