The centers of two bowling balls are $2.0 m$ apart. The mass of one bowling ball is $5.0 K g$ . The mass of the other is $6.0 k g$ . How much gravitational force do they exert on each other?
The universal gravitational constant is: $6.67 \times 10^{- 11} \frac{N . m^{2}}{K g^{2}}$

5.0 \times 10^{- 9} N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15.0 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.0 \times 10^{- 10} N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

30.0 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.4 \times 10^{- 9} N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $5.0 \times 10^{- 10} N$
Given : $M_{1} = 5 k g$ $M_{2} = 6 k g$ $r = 2$ m $G = 6.67 \times 10^{- 11}$ $N m^{2} / k g^{2}$

Gravitational force between them $F = \frac{G M_{1} M_{2}}{r^{2}} = \frac{6.67 \times 10^{- 11} \times 5 \times 6}{2^{2}} = 5 \times 10^{- 10}$ N

Suggest Corrections

Similar questions

Two spherical balls of mass 10 kg each are placed with their centers 10 cm apart. Find the gravitational force of attraction between them. Take $G = 6.67 \times 10^{- 11} N m^{2} k g^{- 2}$

Q. Two spherical balls of mass 10 kg each are placed 10 cm apart. Find the gravitational force of attraction between them.

Q. The bodies of masses

100 k g

and

8100 k g

are held at distance of

1 m

. The gravitational field at a point on the line joining them is zero. The gravitational potential at that point in

J / k g

(G = 6.67 \times 10^{- 11} N . m^{2} / k g^{2})

Two spherical balls of mass 10 kg each are placed 10 cm apart. Find the gravitional force of attraction between them.

Q. The mass of a ball is four times the mass of another ball. When these balls are separated by a distance of

10 c m

, the gravitational force between them is

6.67 \times 10^{- 7} N

. The masses of the two balls are

Join BYJU'S Learning Program

The centers of two bowling balls are 2.0m apart. The mass of one bowling ball is 5.0 Kg. The mass of the other is 6.0 kg. How much gravitational force do they exert on each other?The universal gravitational constant is: 6.67 ×10−11N.m2Kg2

The correct option is D 5.0×10−10NGiven : M1=5kg M2=6kg r=2 m G=6.67×10−11 Nm2/kg2Gravitational force between them F=GM1M2r2=6.67×10−11×5×622=5×10−10 N

The centers of two bowling balls are $2.0 m$ apart. The mass of one bowling ball is $5.0 K g$ . The mass of the other is $6.0 k g$ . How much gravitational force do they exert on each other?
The universal gravitational constant is: $6.67 \times 10^{- 11} \frac{N . m^{2}}{K g^{2}}$

The correct option is D $5.0 \times 10^{- 10} N$
Given : $M_{1} = 5 k g$ $M_{2} = 6 k g$ $r = 2$ m $G = 6.67 \times 10^{- 11}$ $N m^{2} / k g^{2}$

Gravitational force between them $F = \frac{G M_{1} M_{2}}{r^{2}} = \frac{6.67 \times 10^{- 11} \times 5 \times 6}{2^{2}} = 5 \times 10^{- 10}$ N