The centre and radius of the circle 2 x 2-2 y 2- x -0 areA- 1-4- 0 and 1-4B- -1-2- 0 and 1-2C- 1-2- 0 and 1-2D- 0-1-4 and 1-4

Let C be the circle with centre at (1, 1) and radius 1. If T is the circle centred at (0, y) passing through origin and touching the circle C externally, then the radius of T is equal to

Q. Find the centre and radius of the circle:

\frac{1}{2} (x^{2} + y^{2}) + X c o s θ + y s i n θ - 4 = 0

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The centre and radius of the circle 2x2+2y2−x=0 are

The correct option is A (14,0)and14The circle is x2+y2−12x=0. Centre (-g, -f) = (14,0) and R=√116+0−0=14.

The centre and radius of the circle $2 x^{2} + 2 y^{2} - x = 0$ are

The correct option is A $(\frac{1}{4}, 0) a n d \frac{1}{4}$
The circle is $x^{2} + y^{2} - \frac{1}{2} x = 0.$
Centre (-g, -f) = $(\frac{1}{4}, 0)$ and $R = \sqrt{\frac{1}{16} + 0 - 0} = \frac{1}{4} .$