Question

The centre and radius of the circle $2x^2+2y^2-x=0$ are

• A. $(\frac{1}{4},0)and\frac{1}{4}$
• B. $(-\frac{1}{2},0)and\frac{1}{2}$
• C. $(\frac{1}{2},0)and\frac{1}{2}$
• D. $(0,-\frac{1}{4})and\frac{1}{4}$

Answer 1

The correct option is A $(\frac{1}{4},0)and\frac{1}{4}$

The circle is $x^2+y^2-\frac{1}{2}x=0.$
Centre (-g, -f) = $(\frac{1}{4},0)$ and $R=\sqrt{\frac{1}{16}+0-0}=\frac{1}{4}.$