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Question

The centre of a circle always lies on the perpendicular bisector of any given chord.

A
True
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B
False
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Solution

The correct option is A True
Consider a line segment AB, point "C" is a point on the perpendicular bisector of AB. Triangle ABC is a isosceles triangle as AC = BC. We can say that all the points that form a isosceles triangle are on the perpendicular bisector. Now consider a circle with centre "O" and chord EF, OE = OF (radii). This implies OEF is a isosceles triangle. So, point "O" always lies on the perpendicular bisector.

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