Question

The centre of circle inscribed in a square formed by lines $x^2-8x+12=0$ and $y^2-14y+45=0$ is?

• A. $(4,7)$
• B. $(7,4)$
• C. $(9,4)$
• D. $(4,9)$

Answer 1

The correct option is A $(4,7)$

$x^2-8x+12=0⟹x=6,x=2$

$y^2-14y+45=0⟹y=5,y=9$

Center of circle is given by $(\frac{6+2}{2},\frac{5+9}{2})=(4,7)$