The centre of circle $x^{2} + y^{2} + 16 x - 22 y - 20 = 0,$ is

(8, 11)

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(- 8, 11)

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(- 16, 22)

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(11, - 8)

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Solution

The correct option is B $(- 8, 11)$
Given equation of circle $x^{2} + y^{2} + 16 x - 22 y - 20 = 0$
General equation of circle
$x^{2} + y^{2} + 2 g x + 2 f y + c = 0$
Centre of circle
$= (- g, - f) = (- 8, 11)$

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