The centre of circle x 2- y 2-16 x -22 y -20-0- isA- 8-11B- -8-11C- -16-22D- 11-8

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Standard XII

Mathematics

Definition of Circle

The centre of...

Question

The centre of circle $x^{2} + y^{2} + 16 x - 22 y - 20 = 0,$ is

(8, 11)

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(- 8, 11)

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(- 16, 22)

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(11, - 8)

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Solution

The correct option is B $(- 8, 11)$
Given equation of circle $x^{2} + y^{2} + 16 x - 22 y - 20 = 0$
General equation of circle
$x^{2} + y^{2} + 2 g x + 2 f y + c = 0$
Centre of circle
$= (- g, - f) = (- 8, 11)$

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The centre of circle x2+y2+16x−22y−20=0, is

The correct option is B (−8,11)Given equation of circle x2+y2+16x−22y−20=0 General equation of circle x2+y2+2gx+2fy+c=0 Centre of circle =(−g,−f)=(−8,11)

The centre of circle $x^{2} + y^{2} + 16 x - 22 y - 20 = 0,$ is

The correct option is B $(- 8, 11)$
Given equation of circle $x^{2} + y^{2} + 16 x - 22 y - 20 = 0$
General equation of circle
$x^{2} + y^{2} + 2 g x + 2 f y + c = 0$
Centre of circle
$= (- g, - f) = (- 8, 11)$