CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question


The centre of regular polygon of n sides is located at Z=0 and one of its vertices is Z1 lf Z2 is the vertex adjacent to Z1 then Z2=

A
Z1(cos2πn±isin2πn)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Z1(cosπn±isinπn)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Z1(cosπ2n±isinπ2n)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Z1(cosπ3n±isinπ3n)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Z1(cos2πn±isin2πn)
Polygon of n


sides


subsequent vertices subtend angle of 2πn at
origin.


[2π is total angle at centre and there are n sides
each side subtends 2πn]


So,


z2 is adjacent to z1


z2 can either be clockwise (cw) or anticlockwise
(acw) adjacent.


So,


z2=z1ei2π2 or z2=z1ei2π2


z2=z1(cos2πn+isin2πn) or


z2=z1(cos2πnisin2πn)


=z1(cos2πn±+isin2πn)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nuclear Energy
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon