Question

The centre of regular polygon of n sides is located at Z=0 and one of its vertices is Z1 lf Z2 is the vertex adjacent to Z1 then Z2=

A
Z1(cos2πn±isin2πn)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Z1(cosπn±isinπn)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Z1(cosπ2n±isinπ2n)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Z1(cosπ3n±isinπ3n)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Z1(cos2πn±isin2πn)Polygon of nsides⇒ subsequent vertices subtend angle of 2πn atorigin.[∵2π is total angle at centre and there are n sides⇒ each side subtends 2πn]So,z2 is adjacent to z1 ⇒ z2 can either be clockwise (cw) or anticlockwise(acw) adjacent.So,z2=z1ei2π2 or z2=z1e−i2π2⇒ z2=z1(cos2πn+isin2πn) orz2=z1(cos2πn−isin2πn)=z1(cos2πn±+isin2πn)

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Nuclear Energy
MATHEMATICS
Watch in App
Join BYJU'S Learning Program