The centre of the circle represented by $| z + 1 | = 2 | z - 1 |$ on the complex plane is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{5}{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{5}{3}$
$x^{2} + 1 + 2 x + y^{2}$ = ${4 x}^{2} + 4 - 8 x + 4 y^{2}$
we get,
${3 x}^{2} + 3 - 10 x + 3 y^{2} = 0$
${(x - \frac{5}{3})}^{2} + y^{2} = \frac{19}{6}$
so centre is $(\frac{5}{3}, 0)$

Suggest Corrections

Similar questions

| z + 1 | = 2 | z - 1 |

If |z|=2, then the points representing the complex numbers -1+5z will lie on a

∣ ∣ ∣ \frac{z + 1}{z - 1} ∣ ∣ ∣ = 2

\frac{5}{3}

∣ ∣ ∣ \frac{z - 1}{z + 1} ∣ ∣ ∣ = 2

\frac{4}{3}

The points $z_{1}, z_{2}, z_{3} a n d z_{4}$ in the complex plane are the vertices of a parallelogram taken in order if and only if

C_{1}

C_{2}

1

8 / 3

(3, 0)

z

{log}_{1 / 3} (\frac{| z - 3 |^{2} + 2}{11 | z - 3 | - 2}) > 1

Join BYJU'S Learning Program