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Byju's Answer
Standard VIII
Mathematics
Definition of circle
The centre of...
Question
The centre of the circle
x
=
−
1
+
2
c
o
s
θ
,
y
=
3
+
2
s
i
n
θ
,
is
A
(1, -3)
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B
(-1, 3)
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C
(1, 3)
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D
None of these
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Solution
The correct option is
B
(-1, 3)
Given that
x
+
1
2
=
c
o
s
θ
.
Also
y
−
3
2
=
s
i
n
θ
.
⇒
(
x
+
1
2
)
2
+
(
y
−
3
2
)
2
=
1
⇒
(
x
+
1
)
2
+
(
y
−
3
)
2
=
4
,
whose centre is (-1, 3).
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