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Byju's Answer
Standard XII
Mathematics
Parametric Equation of a Circle
The centre of...
Question
The centre of the circle
x
=
1
+
2
cos
θ
,
y
=
−
3
+
2
sin
θ
,
is
A
(
−
1
,
3
)
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B
(
1
,
−
3
)
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C
(
2
,
3
)
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D
(
−
1
2
,
3
2
)
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Solution
The correct option is
B
(
1
,
−
3
)
Given,
x
−
1
2
=
cos
θ
,
y
+
3
2
=
sin
θ
squaring and adding both the equations, we get
(
x
−
1
2
)
2
+
(
y
+
3
2
)
2
=
1
⇒
(
x
−
1
)
2
+
(
y
+
3
)
2
=
2
2
Hence, centre of circle is
(
1
,
−
3
)
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Parametric Equation of a Circle
Standard XII Mathematics
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