The centre of the circle z¯z−(2+3i)z−(2−3i)¯z+9 = 0 is
( 2, -3 )
( 2, 3 )
( -2, -3 )
( -2, 3 )
Centre of the circle z¯z+¯az+a¯z+b = 0 is -a
Centre of the given circle z¯z−(2+3i)z−(2−3i)¯z+9 = 0 is 2−3i, i.e. (2,-3)
The equation z¯z+(2−3i)z+(2+3i)¯z+4 =0 represents a circle of radius