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Question

The centre of the circle z¯z(2+3i)z(23i)¯z+9 = 0 is


A

( 2, -3 )

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B

( 2, 3 )

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C

( -2, -3 )

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D

( -2, 3 )

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Solution

The correct option is A

( 2, -3 )


Centre of the circle z¯z+¯az+a¯z+b = 0 is -a

Centre of the given circle z¯z(2+3i)z(23i)¯z+9 = 0 is 23i, i.e. (2,-3)


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