The centre of the hyperbola 2xy+3x+4y+1=0 is

$(\frac{- 3}{2}, - 2)$

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$(- 2, \frac{- 3}{2})$

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$(2, \frac{3}{2})$

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$(\frac{3}{2}, 2)$

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Solution

The correct option is B
$(- 2, \frac{- 3}{2})$

2xy + 3x + 4y + 1 = 0

2y + 3 = 0 $∣ ∣ ∣$ 2x + 4 = 0

$\to$ y = $\frac{- 3}{2}$ $\to$ x = -2

$c = (- 2, \frac{- 3}{2})$

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