The centre of the smallest circle touching the circles $x^{2} - 2 y - 3 = 0$ and $x^{2} + y^{2} - 8 x - 18 y + 93 = 0$ is :

(3, 2)

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(4, 4)

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(2, 7)

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(2, 5)

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Solution

The correct option is D $(2, 5)$
Hence, Option (D) is the correct answer.

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Similar questions

x^{2} + y^{2} - 2 y - 3 = 0

x^{2} + y^{2} - 8 x - 18 y + 93 = 0

x^{2} + y^{2} - 2 y - 3 = 0

x^{2} + y^{2} - 8 x - 18 y + 93 = 0

x^{2} + y^{2} = 9

Locus of the centre of the circle which touches the two circle $x^{2} + y^{2} + 8 x - 9 = 0 a n d x^{2} + y^{2} - 8 x + 7 = 0$ externally, is

(3, \sqrt{\frac{7}{2}})

x^{2} - y^{2} - 2 x + 1 = 0

x^{2} + y^{2} - 8 x + 10 y + 15 = 0 .

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