The centre of the sun consists of gases whose average molecular weight is 2 - If the density of the gases is 2-73 - 103 kg - m 3 at a pressure of 1-12 - 109 atm- the temperature at the centre of the Sun is assuming ideal behaviorA- 108 KB- 106 CC- 107 KD- 109 K

The correct option is C 107K d = PM /RT ⇒ T = PM/Rd p = 1.12 × 10^9 , d = 2.73 × 10^3 kg / m^3 M= 2 T = 1. 12 ×10^9× 2/22.4/273× 2.73 ×10^3 T = 10^7 K ...

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Standard VII

Physics

Measurement of Volume

The centre of...

Question

The centre of the sun consists of gases whose average molecular weight is 2. If the density of the gases is 2.73 x $10^{3}$ kg/ $m^{3}$ at a pressure of 1.12 x $10^{9}$ atm, the temperature at the centre of the Sun is (assuming ideal behavior)

10⁸K

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10⁶C

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10⁷K

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10⁹K

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Solution

The correct option is C
10⁷K

d = $\frac{P M}{R T}$ $\Rightarrow$ T = $\frac{P M}{R d}$

p = 1.12 $\times$ $10^{9}$ , d = 2.73 $\times$ $10^{3}$ kg / $m^{3}$

M= 2

T = $\frac{1. 12 \times 10^{9} \times 2}{\frac{22.4}{273} \times 2.73 \times 10^{3}}$

T = $10^{7}$ K

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The centre of the sun consists of gases whose average molecular weight is 2. If the density of the gases is 2.73 x 103kg/ m3 at a pressure of 1.12 x 109 atm, the temperature at the centre of the Sun is (assuming ideal behavior)

The correct option is C 107K d = PMRT ⇒ T = PMRd p = 1.12 × 109 , d = 2.73 × 103 kg / m3 M= 2 T = 1.12×109×222.4273×2.73×103 T = 107 K

The centre of the sun consists of gases whose average molecular weight is 2. If the density of the gases is 2.73 x $10^{3}$ kg/ $m^{3}$ at a pressure of 1.12 x $10^{9}$ atm, the temperature at the centre of the Sun is (assuming ideal behavior)

The correct option is C
10⁷K

d = $\frac{P M}{R T}$ $\Rightarrow$ T = $\frac{P M}{R d}$

p = 1.12 $\times$ $10^{9}$ , d = 2.73 $\times$ $10^{3}$ kg / $m^{3}$

M= 2

T = $\frac{1. 12 \times 10^{9} \times 2}{\frac{22.4}{273} \times 2.73 \times 10^{3}}$

T = $10^{7}$ K