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Question

The centre, one vertex and one focus of a hyperbola are (1,−1) , (5,−1) , (6,−1).

The equation of its directrix are:

A
5x21=0,5x+11=0
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B
5x+4=0, x+1=0
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C
5x7=0,5x19=0
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D
5x17=0,5x6=0
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Solution

The correct option is A 5x21=0,5x+11=0
Centre is (1,1)
Vertex is (5,1)
Focus is (6,1)
Since axis of hyperbola is parallel to x.axis
distance between center and vertex is a =4
distance between center and focus is ae=5
e=54
Now coming to general equation of directrices with centre at (0,0) is x=ae
But in our case center of hyperbola is shifted ie (1,1)
equation of directrices will be x1=aeandx1=ae
Substitute the value of a and e
We have
5x21=0and5x+11=0

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