The centre, one vertex and one focus of a hyperbola are (1,−1) , (5,−1) , (6,−1).
The equation of its directrix are:
A
5x−21=0,5x+11=0
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B
5x+4=0,x+1=0
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C
5x−7=0,5x−19=0
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D
5x−17=0,5x−6=0
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Solution
The correct option is A5x−21=0,5x+11=0 Centre is (1,−1) Vertex is (5,−1) Focus is (6,−1) Since axis of hyperbola is parallel to x.axis distance between center and vertex is a =4 distance between center and focus is ae=5 ∴e=54 Now coming to general equation of directrices with centre at (0,0) is x=ae But in our case center of hyperbola is shifted ie (1,−1) equation of directrices will be x−1=aeandx−1=−ae Substitute the value of a and e We have 5x−21=0and5x+11=0