The centres of a set of circle, each of radius 3, lie on the circle x2+y2=25. The locus of any point inside the set of circle is
A
4≤x2+y2≤64
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B
x2+y2≤25
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C
x2+y2≥25
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D
3≤x2+y2≤9
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Solution
The correct option is A4≤x2+y2≤64 Let (h,k) be any point in the set, then the equation of circle is (x−h)2+(y−k)2=9 But (h,k) lies on x2+y2=25, ⇒h2+k2=25 ∴2≤ Distance between the centres of two circles ≤ 8 4≤h2+k2≤64 ∴, Locus of (h,k) is 4≤x2+y2≤64 Hence, option 'A' is correct.