The centres of a set of circle, each of radius 3, lies on the circle x2+y2=25. The locus of any point in the set is
A
4x2+y2=64
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B
x2+4y2=64
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C
x2+4y2=16
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D
4x2+y2=16
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Solution
The correct option is A4x2+y2=64 Centre and radius of the circle x2+y2=25 are (0,0) and 5 respectively. Thus required locus is (5−3)2≤x2+y2≤(5+3)2 ⇒4≤x2+y2≤64