Question

The centripetal force required for a $1000kg$ car traveling at $36kmph$ to take a turn by ${90}^o$ in traveling along an arc of length $628m$ is

• A. $250N$
• B. $500N$
• C. $1000N$
• D. $125N$

Answer 1

Answer: (A)

$250N$

The radius of arc is,

$\frac{\pi r}{2}=628$

$r=\frac{628\times 2}{\pi }$

$r=400m$

velocity in $m/s$ is,

$v=36km/h=36\times \frac{5}{18}=10m/s$

Centripetal force will be,

$F=\frac{m{v}^2}{r}$

$F=\frac{1000\times {10}^2}{400}$

$F=250N$

Thus, centripetal force is $250N$.